1.配置struts1时，需要在web.xml中配置相关信息：
action org.apache.struts.action.ActionServlet config /WEB-INF/struts-config.xml debug 3 detail 3 0 action *.do index.jsp java.lang.Throwable /common/500.jsp 500 /common/500.jsp 404 /common/404.jsp 403 /common/403.jsp DB2 Connection jdbc/DW javax.sql.DataSource Container
2.此外，struts.xml的配置如下：
3.其中的Action继承的是DispatchAction，当访问时，url为contentPath + wbgy.do?method=getAllWBGYXX。以下是action中的一个method对应的方法：
public ActionForward getAllWBGYXX(ActionMapping mapping, ActionForm form, HttpServletRequest request, HttpServletResponse response) throws Exception { List WBGYList = new ArrayList (); HttpSession session = request.getSession(); FgyjdaRsQxYh user = (FgyjdaRsQxYh)session.getAttribute("user"); int qx = (Integer)session.getAttribute("qx"); String param =""; if(qx==3){//本人 param =" where LRRZYBM='"+user.getZybm()+"'"; }else if(qx==6){//本部门 param =" where LRRBMDM="+user.getBmdm()+" and fydm="+user.getFydm(); } WBGYList = wbgyServer.getAllWBGY(param); if(XXX){ request.setAttribute("WBGYList", WBGYList); return mapping.findForward("WBGYList"); }else{ return mapping.findForward("error"); } }
4.需要添加相应的方法只需要增加相应的method方法，转发url的name，根据name重新跳转页面：
public ActionForward getAllWBGYXX(ActionMapping mapping, ActionForm form, HttpServletRequest request, HttpServletResponse response){ //业务处理 return mapping.findForward("xxx");} 5.相关跳转的信息在struts.xml中配置。